https://go.dev/doc/faq#nil_error

This last line of this code sample does not compile.

type T1 int
type T2 int
var t1 T1
var x = T2(t1) // OK
var st1 []T1
var sx = ([]T2)(st1) // NOT OK

In Go, types are closely tied to methods, in that every named type has a (possibly empty) method set. The general rule is that you can change the name of the type being converted (and thus possibly change its method set) but you can't change the name (and method set) of elements of a composite type. Go requires you to be explicit about type conversions.

Why is my nil error value not equal to nil?

Under the covers, interfaces are implemented as two elements, a type T and a value V. V is a concrete value such as an int, struct or pointer, never an interface itself, and has type T. For instance, if we store the int value 3 in an interface, the resulting interface value has, schematically, (T=int, V=3). The value V is also known as the interface's dynamic value, since a given interface variable might hold different values V (and corresponding types T) during the execution of the program.

An interface value is nil only if the V and T are both unset, (T=nil, V is not set), In particular, a nil interface will always hold a nil type. If we store a nil pointer of type *int inside an interface value, the inner type will be *int regardless of the value of the pointer: (T=*int, V=nil). Such an interface value will therefore be non-nil even when the pointer value V inside is nil.

This situation can be confusing, and arises when a nil value is stored inside an interface value such as an error return:

func returnsError() error {
    var p *MyError = nil
    if bad() {
        p = ErrBad
    }
    return p // Will always return a non-nil error.
}

If all goes well, the function returns a nil p, so the return value is an error interface value holding (T=*MyError, V=nil). This means that if the caller compares the returned error to nil, it will always look as if there was an error even if nothing bad happened. To return a proper nil error to the caller, the function must return an explicit nil:

func returnsError() error {
    if bad() {
        return ErrBad
    }
    return nil
}

It's a good idea for functions that return errors always to use the error type in their signature (as we did above) rather than a concrete type such as *MyError, to help guarantee the error is created correctly. As an example, os.Open returns an error even though, if not nil, it's always of concrete type *os.PathError.

Similar situations to those described here can arise whenever interfaces are used. Just keep in mind that if any concrete value has been stored in the interface, the interface will not be nil. For more information, see The Laws of Reflection.

Why are there no untagged unions, as in C?

Untagged unions would violate Go's memory safety guarantees.

Why does Go not have variant types?

Variant types, also known as algebraic types, provide a way to specify that a value might take one of a set of other types, but only those types. A common example in systems programming would specify that an error is, say, a network error, a security error or an application error and allow the caller to discriminate the source of the problem by examining the type of the error. Another example is a syntax tree in which each node can be a different type: declaration, statement, assignment and so on.

We considered adding variant types to Go, but after discussion decided to leave them out because they overlap in confusing ways with interfaces. What would happen if the elements of a variant type were themselves interfaces?